/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<vector<int> > result;
if(root == NULL) {
return result;
}
if(root->left == NULL && root->right == NULL) {
if(sum == root->val) {
vector<int> temp{root->val};
result.emplace_back(temp);
return result;
}
}
if(root->left != NULL) {
auto ret = pathSum(root->left, sum - root->val);
for(vector<int>& v: ret) {
vector<int> newV{root->val};
for(int i : v) {
newV.emplace_back(i);
}
result.emplace_back(newV);
}
}
if(root->right != NULL) {
auto ret = pathSum(root->right, sum - root->val);
for(vector<int>& v: ret) {
vector<int> newV{root->val};
for(int i : v) {
newV.emplace_back(i);
}
result.emplace_back(newV);
}
}
return result;
}
};
4/14/2014
Leetcode -- Path Sum II
Very simple recursion question
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