/**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
vector<Interval> merge(vector<Interval> &intervals) {
vector<Interval> result;
if(intervals.empty()) {
return result;
}
sort(intervals.begin(), intervals.end(), [](Interval i1, Interval i2) {
return i1.start < i2.start;
});
Interval curr(intervals[0]);
for(int i = 1; i < intervals.size(); ++i) {
if(intervals[i].start <= curr.end) {
if(intervals[i].end > curr.end) {
curr.end = intervals[i].end;
}
} else {
result.emplace_back(curr);
curr = intervals[i];
}
}
result.emplace_back(curr);
return result;
}
};
4/15/2014
Leetcode -- Merge Intervals
We have to sort the vector by the start value first.
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