/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode *root, int sum) {
if(root == NULL) {
return false;
}
if(root->left == NULL && root->right == NULL) {
return root->val == sum;
}
if(root->left != NULL) {
if(hasPathSum(root->left, sum - root->val)) {
return true;
}
}
if(root->right != NULL) {
if(hasPathSum(root->right, sum - root->val)) {
return true;
}
}
return false;
}
};
4/13/2014
Leetcode -- Path Sum
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